aspclassic-core/AspClassic.Parser/SimpleName.cs
Jelle Luteijn 484dbfc9d9 progress
2022-05-15 11:19:49 +02:00

74 lines
2 KiB
C#

using System;
namespace AspClassic.Parser;
/// <summary>
/// A parse tree for a simple name (e.g. 'foo').
/// </summary>
public sealed class SimpleName : Name
{
private readonly string _Name;
private readonly TypeCharacter _TypeCharacter;
private readonly bool _Escaped;
/// <summary>
/// The name, if any.
/// </summary>
public string Name => _Name;
/// <summary>
/// The type character.
/// </summary>
public TypeCharacter TypeCharacter => _TypeCharacter;
/// <summary>
/// Whether the name is escaped.
/// </summary>
public bool Escaped => _Escaped;
public override bool IsBad => Name == null;
/// <summary>
/// Creates a bad simple name.
/// </summary>
/// <param name="Span">The location of the parse tree.</param>
/// <returns>A bad simple name.</returns>
public static SimpleName GetBadSimpleName(Span span)
{
return new SimpleName(span);
}
/// <summary>
/// Constructs a new simple name parse tree.
/// </summary>
/// <param name="name">The name, if any.</param>
/// <param name="typeCharacter">The type character.</param>
/// <param name="escaped">Whether the name is escaped.</param>
/// <param name="span">The location of the parse tree.</param>
public SimpleName(string name, TypeCharacter typeCharacter, bool escaped, Span span)
: base(TreeType.SimpleName, span)
{
if (typeCharacter != 0 && escaped)
{
throw new ArgumentException("Escaped named cannot have type characters.");
}
if (typeCharacter != 0 && typeCharacter != TypeCharacter.DecimalSymbol && typeCharacter != TypeCharacter.DoubleSymbol && typeCharacter != TypeCharacter.IntegerSymbol && typeCharacter != TypeCharacter.LongSymbol && typeCharacter != TypeCharacter.SingleSymbol && typeCharacter != TypeCharacter.StringSymbol)
{
throw new ArgumentOutOfRangeException("typeCharacter");
}
if (name == null)
{
throw new ArgumentNullException("name");
}
_Name = name;
_TypeCharacter = typeCharacter;
_Escaped = escaped;
}
private SimpleName(Span span)
: base(TreeType.SimpleName, span)
{
}
}